错误代码1292 Mysql DateTime

DROP PROCEDURE IF EXISTS TESTProc;

DELIMITER //



CREATE PROCEDURE TESTproc()

BEGIN

DECLARE LYEAR VARCHAR(45); 

DECLARE LMONTH VARCHAR(45);

DECLARE LDAY VARCHAR(45);

DECLARE LTIME VARCHAR(45);

DECLARE LDATETIME DATETIME; 

SELECT TIME FROM db.test_table INTO LTIME;

SELECT SUBSTRING(DATE,6,4) FROM db.test_table INTO LYEAR;

SELECT SUBSTRING(DATE,3,2) FROM db.test_table INTO LMONTH;

SELECT SUBSTRING(DATE,1,1) FROM db.test_table INTO LDAY;

SELECT CONCAT(LYEAR,'-', LMONTH,'-','0',LDAY,' ',LTIME) INTO LDATETIME;

INSERT INTO db.test_table(VC19) VALUES (LDATETIME);


END //

Call TESTProc;

当我运行该过程时,我收到一个错误代码：

Call TESTProc;  Error Code: 1292. Incorrect datetime value: '2013-31-01 16:00:40' for column 'LDATETIME' at row 2

我在db.test_table中只有一行.我在表中没有名为’LDATETIME’的列,这只是我的局部变量.我可以从错误中看到我的格式对于DateTime’YYYY-MM-DD HH：MM：SS’是正确的.

为什么我收到此错误？

更新：以下是我的代码现在的样子：

DROP PROCEDURE IF EXISTS DateProc;

DELIMITER //



CREATE PROCEDURE Dateproc()

BEGIN

DECLARE LTIME VARCHAR(45);

DECLARE LDATE VARCHAR(45);

DECLARE LDATETIME DATETIME; 

SELECT TIME FROM db.date_table INTO LTIME;

SELECT DATE FROM db.date_table INTO LDATE;


IF LENGTH(LDATE) = 9 AND SUBSTRING(LDATE,2,1) = '/'
THEN SET LDATETIME = CONCAT(SUBSTRING(LDATE,6,4),'-0',SUBSTRING(LDATE,1,1),'-',SUBSTRING(LDATE,3,2), ' ', LTIME);

ELSE IF LENGTH(LDATE) = 9 AND SUBSTRING(LDATE,3,1) = '/'
THEN SET LDATETIME = CONCAT(SUBSTRING(LDATE,6,4),'-',SUBSTRING(LDATE,1,2),'-0',SUBSTRING(LDATE,4,1), ' ', LTIME);

ELSE IF LENGTH(LDATE) = 10 
THEN SET LDATETIME = CONCAT(SUBSTRING(LDATE,7,4),'-',SUBSTRING(LDATE,1,2),'-',SUBSTRING(LDATE,4,2), ' ', LTIME);

ELSE IF LENGTH(LDATE) = 8 
THEN SET LDATETIME = CONCAT(SUBSTRING(LDATE,5,4),'-0',SUBSTRING(LDATE,1,1),'-0',SUBSTRING(LDATE,3,1), ' ', LTIME);

END IF;

END IF;

END IF; 

END IF;


INSERT INTO db.date_table(table_name) VALUES (LDATETIME);


END //


CALL DateProc;

这似乎有效并且可以解释可能在我的原始日期列中结束的任何变量日期.

'2013-31-01 16:00:40'

那是试图使用31个月.

目前尚不清楚这是否意味着您的测试数据是错误的,或者您是否需要更改这些行：

SELECT SUBSTRING(DATE,3,2) FROM db.test_table INTO LMONTH;
SELECT SUBSTRING(DATE,1,1) FROM db.test_table INTO LDAY;

至：

SELECT SUBSTRING(DATE,1,2) FROM db.test_table INTO LMONTH;
SELECT SUBSTRING(DATE,4,2) FROM db.test_table INTO LDAY;

请注意,从1开始的子字符串从1变为2,并且第二个起始位置从3变为4.您需要两位数的月和日值,对吗？如果您的数据格式实际上是D / M / YYYY(即仅在需要时使用两位数字),那么您将无法使用固定子字符串位置.